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  2. [stextbox id=”question”]
    How many factors are there in 900 and how did you find that using the rule you taught me about counting factors in the instruction unit plz advice

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    1. Start by taking the prime factorization of 900. We know 900 is a perfect square, 900 = 30 x30, so it will have an odd number of factors.
      900 = 30 x 30 = (6 x 5) x (6 x 5) = (2 x 3 x 5) x (2 x 3 x 5) = (2 x 2) x (3 x 3) x (5 x 5) = 223252
      There are 3 prime factors; 2, 3, and 5. Each one is raised to the power of 2 or squared.
      Recall the rule to count the factors is to add 1 to the power of each prime factor and multiply them all out. In this case that is,
      (2+1) x (2+1) x (2+1) = 3 x 3 x 3 = 27 factors including 1 and the number itself.

  3. I don’t really understand number 38. I can get as far as finding the rate(8), but then I don’t really understand what is happening after that point.

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