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Could someone please explain question number 6 please. I don’t recall learning it thank you
I believe the question is…what percent of 20 is 66?
This is an example where practice can be helpful because in most cases the question might be written 66 is what percent of 20? More students are apt to recognize that wording. This is the same question, but the wording is just turned around.
Let’s take it piece by piece.
“what percent” means N% where N is the variable representing the unknown “what” you must solve for.
“of 20” means x 20. “Of” typically means multiplication.
“is 66” means = 66. “Is” typically means equals.
Putting it together that results in the following equation.
N% x 20 = 66 and solving by dividing both sides by 20 to isolate the N%,
N% = 66/20= 3.3 = 330%
Check the result to make sure it makes sense. 66 is about three times 20 or about 300% so this looks about right (at least in the ballpark). If the answer were 30.3 then the question would have to be written something like 20 is what percent of 66 not what percent of 20 is 66. Do you see the difference even though the numbers are presented in the same order? That is the key to the problem! The ordering is designed to be a little tricky and draw students into the 30.3% answer.
There are similar samples for reference in the algebra/word problems classroom instruction unit. That would be a good lesson to review.
Thank you very much
What can I take that doesn’t require paying? Any practice drills of free exams on this site for me?
You can access the BCA sample exam and problem sets under the Exams menu. You will have to sign up for the Free BCA Samples subscription, but that does not require any payment.
On my test, I got a certain amount of problems right, but then it took off points due to deductions. What exactly are deductions and how do they occur?
You receive deductions on most exams in the same manner you will get deductions for wrong answers on the real test. The deduction for an incorrect answer is 1/4 the value of the correct answer. There is no deduction (or points added) for an unasnwered question. The result is your expected value for any question is zero to prevent anyone from using a system to beat the test. In other words, there are 4 incorrect answers or 4 x -(1/4)=-1 point in sub-total for all wrong answers and +1 point for a correct answer out of 5 answer choices. The combined total is 1 – 1 = 0 points so guessing randomly does not provide you any advantage versus not answering which will provide a certain 0 score for that question. It is important to note there is a cost to incorrect answers so a risk averse person may choose to not answer rather than guess, but if you can eliminate 1 or more answers you will improve your expected score by guessing even if you cannot decide between the remaining answers. Does that make it clear?